13301125332401 has 4 divisors (see below), whose sum is σ = 13301136932352. Its totient is φ = 13301113732452.

The previous prime is 13301125332371. The next prime is 13301125332433. The reversal of 13301125332401 is 10423352110331.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13301125332401 - 2³⁰ = 13300051590577 is a prime.

It is a super-2 number, since 2×13301125332401² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13301125232401) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3864761 + ... + 6445046.

It is an arithmetic number, because the mean of its divisors is an integer number (3325284233088).

Almost surely, 2^{13301125332401} is an apocalyptic number.

It is an amenable number.

13301125332401 is a deficient number, since it is larger than the sum of its proper divisors (11599951).

13301125332401 is a wasteful number, since it uses less digits than its factorization.

13301125332401 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 11599950.

The product of its (nonzero) digits is 6480, while the sum is 29.

Adding to 13301125332401 its reverse (10423352110331), we get a palindrome (23724477442732).

The spelling of 13301125332401 in words is "thirteen trillion, three hundred one billion, one hundred twenty-five million, three hundred thirty-two thousand, four hundred one".