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13301132011200 = 26325211287929167
BaseRepresentation
bin1100000110001110100100…
…1111111010011011000000
31202002120112202111200110100
43001203221033322123000
53220411204243324300
644142242232402400
72541655310433165
oct301435117723300
952076482450410
1013301132011200
114268a84295840
1215a9a22246400
137563a3195227
1433dac763a06c
15180ed6401700
hexc18e93fa6c0

13301132011200 has 504 divisors, whose sum is σ = 51592806420480. Its totient is φ = 3223286323200.

The previous prime is 13301132011187. The next prime is 13301132011201. The reversal of 13301132011200 is 211023110331.

13301132011200 is a `hidden beast` number, since 1 + 330 + 1 + 1 + 320 + 1 + 12 + 0 + 0 = 666.

It is a super-2 number, since 2×133011320112002 (a number of 27 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is not an unprimeable number, because it can be changed into a prime (13301132011201) by changing a digit.

It is a polite number, since it can be written in 71 ways as a sum of consecutive naturals, for example, 456019017 + ... + 456048183.

Almost surely, 213301132011200 is an apocalyptic number.

13301132011200 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13301132011200, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (25796403210240).

13301132011200 is an abundant number, since it is smaller than the sum of its proper divisors (38291674409280).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13301132011200 is a wasteful number, since it uses less digits than its factorization.

13301132011200 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 32085 (or 32067 counting only the distinct ones).

The product of its (nonzero) digits is 108, while the sum is 18.

Adding to 13301132011200 its reverse (211023110331), we get a palindrome (13512155121531).

The spelling of 13301132011200 in words is "thirteen trillion, three hundred one billion, one hundred thirty-two million, eleven thousand, two hundred".