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13301142102241 = 71900163157463
BaseRepresentation
bin1100000110001110100111…
…0110011010000011100001
31202002120120110111100202121
43001203221312122003201
53220411214334232431
644142243232544241
72541655462262140
oct301435166320341
952076513440677
1013301142102241
114268a89a58344
1215a9a256b2081
137563a52b9366
1433dac8b05757
15180ed7246611
hexc18e9d9a0e1

13301142102241 has 4 divisors (see below), whose sum is σ = 15201305259712. Its totient is φ = 11400978944772.

The previous prime is 13301142102229. The next prime is 13301142102251. The reversal of 13301142102241 is 14220124110331.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13301142102241 - 215 = 13301142069473 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13301142102251) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 950081578725 + ... + 950081578738.

It is an arithmetic number, because the mean of its divisors is an integer number (3800326314928).

Almost surely, 213301142102241 is an apocalyptic number.

It is an amenable number.

13301142102241 is a deficient number, since it is larger than the sum of its proper divisors (1900163157471).

13301142102241 is an equidigital number, since it uses as much as digits as its factorization.

13301142102241 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1900163157470.

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 13301142102241 its reverse (14220124110331), we get a palindrome (27521266212572).

The spelling of 13301142102241 in words is "thirteen trillion, three hundred one billion, one hundred forty-two million, one hundred two thousand, two hundred forty-one".

Divisors: 1 7 1900163157463 13301142102241