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1330114442411 = 6221213810391
BaseRepresentation
bin10011010110110000111…
…111111011010010101011
311201011020221222122002002
4103112300333323102223
5133243033244124121
62455013544401215
7165045322133516
oct23266077732253
94634227878062
101330114442411
11473109a21527
1219595077620b
13985770bb931
1448540ca3d7d
15248ecb07e0b
hex135b0ffb4ab

1330114442411 has 4 divisors (see below), whose sum is σ = 1330328259024. Its totient is φ = 1329900625800.

The previous prime is 1330114442383. The next prime is 1330114442413. The reversal of 1330114442411 is 1142444110331.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1330114442411 - 230 = 1329040700587 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1330114442413) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 106898975 + ... + 106911416.

It is an arithmetic number, because the mean of its divisors is an integer number (332582064756).

Almost surely, 21330114442411 is an apocalyptic number.

1330114442411 is a deficient number, since it is larger than the sum of its proper divisors (213816613).

1330114442411 is an equidigital number, since it uses as much as digits as its factorization.

1330114442411 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 213816612.

The product of its (nonzero) digits is 4608, while the sum is 29.

Adding to 1330114442411 its reverse (1142444110331), we get a palindrome (2472558552742).

The spelling of 1330114442411 in words is "one trillion, three hundred thirty billion, one hundred fourteen million, four hundred forty-two thousand, four hundred eleven".

Divisors: 1 6221 213810391 1330114442411