133012330440001 has 4 divisors (see below), whose sum is σ = 133258194267604. Its totient is φ = 132766466612400.

The previous prime is 133012330439981. The next prime is 133012330440023. The reversal of 133012330440001 is 100044033210331.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 40601619363600 + 92410711076401 = 6371940^2 + 9613049^2 .

It is a cyclic number.

It is not a de Polignac number, because 133012330440001 - 2⁹ = 133012330439489 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (133012330440401) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 122931912990 + ... + 122931914071.

It is an arithmetic number, because the mean of its divisors is an integer number (33314548566901).

Almost surely, 2^{133012330440001} is an apocalyptic number.

It is an amenable number.

133012330440001 is a deficient number, since it is larger than the sum of its proper divisors (245863827603).

133012330440001 is an equidigital number, since it uses as much as digits as its factorization.

133012330440001 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 245863827602.

The product of its (nonzero) digits is 2592, while the sum is 25.

Adding to 133012330440001 its reverse (100044033210331), we get a palindrome (233056363650332).

The spelling of 133012330440001 in words is "one hundred thirty-three trillion, twelve billion, three hundred thirty million, four hundred forty thousand, one".