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13301233113000 = 2335372127712477
BaseRepresentation
bin1100000110001110111101…
…0001100101011110101000
31202002120210210202012001110
43001203233101211132220
53220411411134104000
644142300243350320
72541660645664500
oct301435721453650
952076723665043
1013301233113000
11426902636a048
1215a9a500823a0
137563bb103391
1433dad6c36a00
15180ee0222850
hexc18ef4657a8

13301233113000 has 384 divisors, whose sum is σ = 48655521607680. Its totient is φ = 3016338393600.

The previous prime is 13301233112971. The next prime is 13301233113011. The reversal of 13301233113000 is 31133210331.

13301233113000 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a Harshad number since it is a multiple of its sum of digits (21).

It is an unprimeable number.

It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 18312762 + ... + 19025238.

It is an arithmetic number, because the mean of its divisors is an integer number (126707087520).

Almost surely, 213301233113000 is an apocalyptic number.

13301233113000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13301233113000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (24327760803840).

13301233113000 is an abundant number, since it is smaller than the sum of its proper divisors (35354288494680).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13301233113000 is a wasteful number, since it uses less digits than its factorization.

13301233113000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 712642 (or 712621 counting only the distinct ones).

The product of its (nonzero) digits is 486, while the sum is 21.

Adding to 13301233113000 its reverse (31133210331), we get a palindrome (13332366323331).

The spelling of 13301233113000 in words is "thirteen trillion, three hundred one billion, two hundred thirty-three million, one hundred thirteen thousand".