Base | Representation |
---|---|
bin | 1100000110001111101101… |
… | …0001001001010000100011 |
3 | 1202002121022211100202122211 |
4 | 3001203323101021100203 |
5 | 3220412314141332003 |
6 | 44142332232142551 |
7 | 2541665641154500 |
oct | 301437321112043 |
9 | 52077284322584 |
10 | 13301434324003 |
11 | 42691199a9931 |
12 | 15a9aa7537a57 |
13 | 7564209c2947 |
14 | 33db158524a7 |
15 | 181002c1a96d |
hex | c18fb449423 |
13301434324003 has 24 divisors (see below), whose sum is σ = 16287756406800. Its totient is φ = 10800975181248.
The previous prime is 13301434323977. The next prime is 13301434324093. The reversal of 13301434324003 is 30042343410331.
It is not a de Polignac number, because 13301434324003 - 213 = 13301434315811 is a prime.
It is not an unprimeable number, because it can be changed into a prime (13301434324093) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 81463801 + ... + 81626917.
It is an arithmetic number, because the mean of its divisors is an integer number (678656516950).
Almost surely, 213301434324003 is an apocalyptic number.
13301434324003 is a deficient number, since it is larger than the sum of its proper divisors (2986322082797).
13301434324003 is a wasteful number, since it uses less digits than its factorization.
13301434324003 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 250739 (or 250732 counting only the distinct ones).
The product of its (nonzero) digits is 31104, while the sum is 31.
Adding to 13301434324003 its reverse (30042343410331), we get a palindrome (43343777734334).
The spelling of 13301434324003 in words is "thirteen trillion, three hundred one billion, four hundred thirty-four million, three hundred twenty-four thousand, three".
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