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1330201314241 = 1783746046727
BaseRepresentation
bin10011010110110110001…
…011010100001111000001
311201011111000110011211021
4103112312023110033001
5133243223014023431
62455030330345441
7165050425420252
oct23266613241701
94634430404737
101330201314241
11473153a66628
1219597588b281
139858c0b6a97
144854c638b29
1524905567b11
hex135b62d43c1

1330201314241 has 4 divisors (see below), whose sum is σ = 1330947362752. Its totient is φ = 1329455265732.

The previous prime is 1330201314199. The next prime is 1330201314257. The reversal of 1330201314241 is 1424131020331.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1330201314241 - 29 = 1330201313729 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1330205314241) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 373021581 + ... + 373025146.

It is an arithmetic number, because the mean of its divisors is an integer number (332736840688).

Almost surely, 21330201314241 is an apocalyptic number.

It is an amenable number.

1330201314241 is a deficient number, since it is larger than the sum of its proper divisors (746048511).

1330201314241 is an equidigital number, since it uses as much as digits as its factorization.

1330201314241 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 746048510.

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 1330201314241 its reverse (1424131020331), we get a palindrome (2754332334572).

The spelling of 1330201314241 in words is "one trillion, three hundred thirty billion, two hundred one million, three hundred fourteen thousand, two hundred forty-one".

Divisors: 1 1783 746046727 1330201314241