Base | Representation |
---|---|
bin | 11110001111101100110110… |
… | …011110010100100011000011 |
3 | 122102222121202121221121121220 |
4 | 132033230312132110203003 |
5 | 114413401132041330223 |
6 | 1150524411531450123 |
7 | 40006255115365110 |
oct | 3617546636244303 |
9 | 572877677847556 |
10 | 133020346042563 |
11 | 39425680564911 |
12 | 12b042988b6943 |
13 | 592b9c338b815 |
14 | 24bc30d2d7907 |
15 | 105a27010e6e3 |
hex | 78fb367948c3 |
133020346042563 has 32 divisors (see below), whose sum is σ = 205476221087232. Its totient is φ = 74969688672000.
The previous prime is 133020346042543. The next prime is 133020346042579. The reversal of 133020346042563 is 365240643020331.
It is not a de Polignac number, because 133020346042563 - 212 = 133020346038467 is a prime.
It is a super-2 number, since 2×1330203460425632 (a number of 29 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (133020346042543) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 201813888 + ... + 202471938.
It is an arithmetic number, because the mean of its divisors is an integer number (6421131908976).
Almost surely, 2133020346042563 is an apocalyptic number.
133020346042563 is a deficient number, since it is larger than the sum of its proper divisors (72455875044669).
133020346042563 is a wasteful number, since it uses less digits than its factorization.
133020346042563 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 789995.
The product of its (nonzero) digits is 933120, while the sum is 42.
Adding to 133020346042563 its reverse (365240643020331), we get a palindrome (498260989062894).
The spelling of 133020346042563 in words is "one hundred thirty-three trillion, twenty billion, three hundred forty-six million, forty-two thousand, five hundred sixty-three".
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