Base | Representation |
---|---|
bin | 10011010110110110010… |
… | …101100111001010110010 |
3 | 11201011111012112022010222 |
4 | 103112312111213022302 |
5 | 133243224211410414 |
6 | 2455030504253042 |
7 | 165050460361115 |
oct | 23266625471262 |
9 | 4634435468128 |
10 | 1330204013234 |
11 | 47315553a3a8 |
12 | 195976771182 |
13 | 9858c820415 |
14 | 4854cb3c57c |
15 | 249058ec68e |
hex | 135b65672b2 |
1330204013234 has 4 divisors (see below), whose sum is σ = 1995306019854. Its totient is φ = 665102006616.
The previous prime is 1330204013179. The next prime is 1330204013261. The reversal of 1330204013234 is 4323104020331.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 1160150872609 + 170053140625 = 1077103^2 + 412375^2 .
It is a Curzon number.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 332551003307 + ... + 332551003310.
Almost surely, 21330204013234 is an apocalyptic number.
1330204013234 is a deficient number, since it is larger than the sum of its proper divisors (665102006620).
1330204013234 is an equidigital number, since it uses as much as digits as its factorization.
1330204013234 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 665102006619.
The product of its (nonzero) digits is 5184, while the sum is 26.
Adding to 1330204013234 its reverse (4323104020331), we get a palindrome (5653308033565).
The spelling of 1330204013234 in words is "one trillion, three hundred thirty billion, two hundred four million, thirteen thousand, two hundred thirty-four".
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