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1330204013234 = 2665102006617
BaseRepresentation
bin10011010110110110010…
…101100111001010110010
311201011111012112022010222
4103112312111213022302
5133243224211410414
62455030504253042
7165050460361115
oct23266625471262
94634435468128
101330204013234
1147315553a3a8
12195976771182
139858c820415
144854cb3c57c
15249058ec68e
hex135b65672b2

1330204013234 has 4 divisors (see below), whose sum is σ = 1995306019854. Its totient is φ = 665102006616.

The previous prime is 1330204013179. The next prime is 1330204013261. The reversal of 1330204013234 is 4323104020331.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 1160150872609 + 170053140625 = 1077103^2 + 412375^2 .

It is a Curzon number.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 332551003307 + ... + 332551003310.

Almost surely, 21330204013234 is an apocalyptic number.

1330204013234 is a deficient number, since it is larger than the sum of its proper divisors (665102006620).

1330204013234 is an equidigital number, since it uses as much as digits as its factorization.

1330204013234 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 665102006619.

The product of its (nonzero) digits is 5184, while the sum is 26.

Adding to 1330204013234 its reverse (4323104020331), we get a palindrome (5653308033565).

The spelling of 1330204013234 in words is "one trillion, three hundred thirty billion, two hundred four million, thirteen thousand, two hundred thirty-four".

Divisors: 1 2 665102006617 1330204013234