13302064241645 has 4 divisors (see below), whose sum is σ = 15962477089980. Its totient is φ = 10641651393312.

The previous prime is 13302064241579. The next prime is 13302064241663. The reversal of 13302064241645 is 54614246020331.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 6768754432489 + 6533309809156 = 2601683^2 + 2556034^2 .

It is a cyclic number.

It is not a de Polignac number, because 13302064241645 - 2¹⁶ = 13302064176109 is a prime.

It is a super-3 number, since 3×13302064241645³ (a number of 40 digits) contains 333 as substring.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1330206424160 + ... + 1330206424169.

It is an arithmetic number, because the mean of its divisors is an integer number (3990619272495).

Almost surely, 2^{13302064241645} is an apocalyptic number.

It is an amenable number.

13302064241645 is a deficient number, since it is larger than the sum of its proper divisors (2660412848335).

13302064241645 is an equidigital number, since it uses as much as digits as its factorization.

13302064241645 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2660412848334.

The product of its (nonzero) digits is 414720, while the sum is 41.

The spelling of 13302064241645 in words is "thirteen trillion, three hundred two billion, sixty-four million, two hundred forty-one thousand, six hundred forty-five".