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133021011041543 = 1266911049964173
BaseRepresentation
bin11110001111101101011110…
…000111000101110100000111
3122102222200110222021001201202
4132033231132013011310013
5114413404012311312133
61150525001525013115
740006310441651462
oct3617553607056407
9572880428231652
10133021011041543
1139425991978449
1212b0444355419b
13592ba9b094841
1424bc3737602d9
15105a2ad6bb2e8
hex78fb5e1c5d07

133021011041543 has 4 divisors (see below), whose sum is σ = 133022061132408. Its totient is φ = 133019960950680.

The previous prime is 133021011041537. The next prime is 133021011041609. The reversal of 133021011041543 is 345140110120331.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 133021011041543 - 242 = 128622964530439 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (133021011041843) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 524855396 + ... + 525108777.

It is an arithmetic number, because the mean of its divisors is an integer number (33255515283102).

Almost surely, 2133021011041543 is an apocalyptic number.

133021011041543 is a deficient number, since it is larger than the sum of its proper divisors (1050090865).

133021011041543 is a wasteful number, since it uses less digits than its factorization.

133021011041543 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1050090864.

The product of its (nonzero) digits is 4320, while the sum is 29.

Adding to 133021011041543 its reverse (345140110120331), we get a palindrome (478161121161874).

The spelling of 133021011041543 in words is "one hundred thirty-three trillion, twenty-one billion, eleven million, forty-one thousand, five hundred forty-three".

Divisors: 1 126691 1049964173 133021011041543