Base | Representation |
---|---|
bin | 11110001111101101011110… |
… | …000111000101110100000111 |
3 | 122102222200110222021001201202 |
4 | 132033231132013011310013 |
5 | 114413404012311312133 |
6 | 1150525001525013115 |
7 | 40006310441651462 |
oct | 3617553607056407 |
9 | 572880428231652 |
10 | 133021011041543 |
11 | 39425991978449 |
12 | 12b0444355419b |
13 | 592ba9b094841 |
14 | 24bc3737602d9 |
15 | 105a2ad6bb2e8 |
hex | 78fb5e1c5d07 |
133021011041543 has 4 divisors (see below), whose sum is σ = 133022061132408. Its totient is φ = 133019960950680.
The previous prime is 133021011041537. The next prime is 133021011041609. The reversal of 133021011041543 is 345140110120331.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 133021011041543 - 242 = 128622964530439 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (133021011041843) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 524855396 + ... + 525108777.
It is an arithmetic number, because the mean of its divisors is an integer number (33255515283102).
Almost surely, 2133021011041543 is an apocalyptic number.
133021011041543 is a deficient number, since it is larger than the sum of its proper divisors (1050090865).
133021011041543 is a wasteful number, since it uses less digits than its factorization.
133021011041543 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1050090864.
The product of its (nonzero) digits is 4320, while the sum is 29.
Adding to 133021011041543 its reverse (345140110120331), we get a palindrome (478161121161874).
The spelling of 133021011041543 in words is "one hundred thirty-three trillion, twenty-one billion, eleven million, forty-one thousand, five hundred forty-three".
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