Base | Representation |
---|---|
bin | 11000110001101111… |
… | …00100111001010010 |
3 | 1021100001021220211111 |
4 | 30120313210321102 |
5 | 204220320432424 |
6 | 10035542403534 |
7 | 650432121646 |
oct | 143067447122 |
9 | 37301256744 |
10 | 13302124114 |
11 | 570677a804 |
12 | 26b2a305aa |
13 | 133cb64576 |
14 | 902932c26 |
15 | 52cc30194 |
hex | 318de4e52 |
13302124114 has 4 divisors (see below), whose sum is σ = 19953186174. Its totient is φ = 6651062056.
The previous prime is 13302124111. The next prime is 13302124117. The reversal of 13302124114 is 41142120331.
13302124114 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It is an interprime number because it is at equal distance from previous prime (13302124111) and next prime (13302124117).
It can be written as a sum of positive squares in only one way, i.e., 9685905889 + 3616218225 = 98417^2 + 60135^2 .
It is not an unprimeable number, because it can be changed into a prime (13302124111) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3325531027 + ... + 3325531030.
Almost surely, 213302124114 is an apocalyptic number.
13302124114 is a deficient number, since it is larger than the sum of its proper divisors (6651062060).
13302124114 is an equidigital number, since it uses as much as digits as its factorization.
13302124114 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6651062059.
The product of its (nonzero) digits is 576, while the sum is 22.
Adding to 13302124114 its reverse (41142120331), we get a palindrome (54444244445).
The spelling of 13302124114 in words is "thirteen billion, three hundred two million, one hundred twenty-four thousand, one hundred fourteen".
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