133023151124333 has 4 divisors (see below), whose sum is σ = 133023186615168. Its totient is φ = 133023115633500.

The previous prime is 133023151124323. The next prime is 133023151124401. The reversal of 133023151124333 is 333421151320331.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 133023151124333 - 2³² = 133018856157037 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 133023151124293 and 133023151124302.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (133023151124323) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 11356541 + ... + 19875042.

It is an arithmetic number, because the mean of its divisors is an integer number (33255796653792).

Almost surely, 2^{133023151124333} is an apocalyptic number.

It is an amenable number.

133023151124333 is a deficient number, since it is larger than the sum of its proper divisors (35490835).

133023151124333 is an equidigital number, since it uses as much as digits as its factorization.

133023151124333 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 35490834.

The product of its (nonzero) digits is 58320, while the sum is 35.

The spelling of 133023151124333 in words is "one hundred thirty-three trillion, twenty-three billion, one hundred fifty-one million, one hundred twenty-four thousand, three hundred thirty-three".