1330233131113 has 4 divisors (see below), whose sum is σ = 1348968809088. Its totient is φ = 1311497453140.

The previous prime is 1330233131111. The next prime is 1330233131147. The reversal of 1330233131113 is 3111313320331.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1330233131113 - 2¹ = 1330233131111 is a prime.

It is a super-4 number, since 4×1330233131113⁴ (a number of 50 digits) contains 4444 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1330233131111) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9367838881 + ... + 9367839022.

It is an arithmetic number, because the mean of its divisors is an integer number (337242202272).

Almost surely, 2^{1330233131113} is an apocalyptic number.

It is an amenable number.

1330233131113 is a deficient number, since it is larger than the sum of its proper divisors (18735677975).

1330233131113 is an equidigital number, since it uses as much as digits as its factorization.

1330233131113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 18735677974.

The product of its (nonzero) digits is 1458, while the sum is 25.

Adding to 1330233131113 its reverse (3111313320331), we get a palindrome (4441546451444).

The spelling of 1330233131113 in words is "one trillion, three hundred thirty billion, two hundred thirty-three million, one hundred thirty-one thousand, one hundred thirteen".