Base | Representation |
---|---|
bin | 1100000110010011000111… |
… | …0110101110001110111101 |
3 | 1202002200200122122021010110 |
4 | 3001210301312232032331 |
5 | 3220421203114110240 |
6 | 44143003145300233 |
7 | 2542030431414105 |
oct | 301446166561675 |
9 | 52080618567113 |
10 | 13302350144445 |
11 | 426954995732a |
12 | 15aa102194679 |
13 | 75653866822b |
14 | 33dba132a205 |
15 | 18105831ec80 |
hex | c1931dae3bd |
13302350144445 has 16 divisors (see below), whose sum is σ = 21287318936832. Its totient is φ = 7093400508480.
The previous prime is 13302350144441. The next prime is 13302350144497. The reversal of 13302350144445 is 54444105320331.
It is not a de Polignac number, because 13302350144445 - 22 = 13302350144441 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13302350144441) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 74046997 + ... + 74226426.
It is an arithmetic number, because the mean of its divisors is an integer number (1330457433552).
Almost surely, 213302350144445 is an apocalyptic number.
13302350144445 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
It is an amenable number.
13302350144445 is a deficient number, since it is larger than the sum of its proper divisors (7984968792387).
13302350144445 is a wasteful number, since it uses less digits than its factorization.
13302350144445 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 148279412.
The product of its (nonzero) digits is 345600, while the sum is 39.
Adding to 13302350144445 its reverse (54444105320331), we get a palindrome (67746455464776).
The spelling of 13302350144445 in words is "thirteen trillion, three hundred two billion, three hundred fifty million, one hundred forty-four thousand, four hundred forty-five".
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