13302423021441 has 4 divisors (see below), whose sum is σ = 17736564028592. Its totient is φ = 8868282014292.

The previous prime is 13302423021421. The next prime is 13302423021449. The reversal of 13302423021441 is 14412032420331.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 13302423021441 - 2¹³ = 13302423013249 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13302423021399 and 13302423021408.

It is not an unprimeable number, because it can be changed into a prime (13302423021449) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2217070503571 + ... + 2217070503576.

It is an arithmetic number, because the mean of its divisors is an integer number (4434141007148).

Almost surely, 2^{13302423021441} is an apocalyptic number.

It is an amenable number.

13302423021441 is a deficient number, since it is larger than the sum of its proper divisors (4434141007151).

13302423021441 is an equidigital number, since it uses as much as digits as its factorization.

13302423021441 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4434141007150.

The product of its (nonzero) digits is 13824, while the sum is 30.

Adding to 13302423021441 its reverse (14412032420331), we get a palindrome (27714455441772).

The spelling of 13302423021441 in words is "thirteen trillion, three hundred two billion, four hundred twenty-three million, twenty-one thousand, four hundred forty-one".