Base | Representation |
---|---|
bin | 1100000110010011011010… |
… | …1111001001000110001011 |
3 | 1202002200220100202011101012 |
4 | 3001210312233021012023 |
5 | 3220421340100342103 |
6 | 44143015232514135 |
7 | 2542032444506426 |
oct | 301446657110613 |
9 | 52080810664335 |
10 | 13302432043403 |
11 | 4269591105218 |
12 | 15aa1256ab94b |
13 | 75654c611a59 |
14 | 33dbac1689bd |
15 | 1810605eb2d8 |
hex | c1936bc918b |
13302432043403 has 4 divisors (see below), whose sum is σ = 13302446373720. Its totient is φ = 13302417713088.
The previous prime is 13302432043391. The next prime is 13302432043421. The reversal of 13302432043403 is 30434023420331.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13302432043403 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 13302432043403.
It is not an unprimeable number, because it can be changed into a prime (13302432043463) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5668550 + ... + 7664027.
It is an arithmetic number, because the mean of its divisors is an integer number (3325611593430).
Almost surely, 213302432043403 is an apocalyptic number.
13302432043403 is a deficient number, since it is larger than the sum of its proper divisors (14330317).
13302432043403 is an equidigital number, since it uses as much as digits as its factorization.
13302432043403 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 14330316.
The product of its (nonzero) digits is 62208, while the sum is 32.
Adding to 13302432043403 its reverse (30434023420331), we get a palindrome (43736455463734).
The spelling of 13302432043403 in words is "thirteen trillion, three hundred two billion, four hundred thirty-two million, forty-three thousand, four hundred three".
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