Base | Representation |
---|---|
bin | 10011010110111000101… |
… | …110010001111000110111 |
3 | 11201011120222211120110101 |
4 | 103112320232101320313 |
5 | 133243314433042403 |
6 | 2455034454134531 |
7 | 165051454504045 |
oct | 23267056217067 |
9 | 4634528746411 |
10 | 1330244034103 |
11 | 4731760946a6 |
12 | 195988051447 |
13 | 98597bc35ca |
14 | 48554199395 |
15 | 249091a571d |
hex | 135b8b91e37 |
1330244034103 has 4 divisors (see below), whose sum is σ = 1330324931200. Its totient is φ = 1330163137008.
The previous prime is 1330244034061. The next prime is 1330244034107. The reversal of 1330244034103 is 3014304420331.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1330244034103 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1330244034107) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 40423878 + ... + 40456771.
It is an arithmetic number, because the mean of its divisors is an integer number (332581232800).
Almost surely, 21330244034103 is an apocalyptic number.
1330244034103 is a deficient number, since it is larger than the sum of its proper divisors (80897097).
1330244034103 is an equidigital number, since it uses as much as digits as its factorization.
1330244034103 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 80897096.
The product of its (nonzero) digits is 10368, while the sum is 28.
Adding to 1330244034103 its reverse (3014304420331), we get a palindrome (4344548454434).
The spelling of 1330244034103 in words is "one trillion, three hundred thirty billion, two hundred forty-four million, thirty-four thousand, one hundred three".
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