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1330310403113 = 1741976371227
BaseRepresentation
bin10011010110111100101…
…011011101010000101001
311201011202121201110121212
4103112330223131100221
5133243433430344423
62455045224442505
7165053221565516
oct23267453352051
94634677643555
101330310403113
114731aa5a571a
121959a6319435
13985a8890503
144855cd1430d
152490ee15578
hex135bcadd429

1330310403113 has 4 divisors (see below), whose sum is σ = 1330386791760. Its totient is φ = 1330234014468.

The previous prime is 1330310403007. The next prime is 1330310403127. The reversal of 1330310403113 is 3113040130331.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1330310403113 - 214 = 1330310386729 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1330310403143) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 38168195 + ... + 38203032.

It is an arithmetic number, because the mean of its divisors is an integer number (332596697940).

Almost surely, 21330310403113 is an apocalyptic number.

It is an amenable number.

1330310403113 is a deficient number, since it is larger than the sum of its proper divisors (76388647).

1330310403113 is an equidigital number, since it uses as much as digits as its factorization.

1330310403113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 76388646.

The product of its (nonzero) digits is 972, while the sum is 23.

Adding to 1330310403113 its reverse (3113040130331), we get a palindrome (4443350533444).

The spelling of 1330310403113 in words is "one trillion, three hundred thirty billion, three hundred ten million, four hundred three thousand, one hundred thirteen".

Divisors: 1 17419 76371227 1330310403113