Base | Representation |
---|---|
bin | 111101111100101000… |
… | …1100101000111000011 |
3 | 110201101011120211101001 |
4 | 1323321101211013003 |
5 | 4134421433412430 |
6 | 141040315152431 |
7 | 12416431103236 |
oct | 1737121450703 |
9 | 421334524331 |
10 | 133031154115 |
11 | 51466689082 |
12 | 21947a45717 |
13 | c710b76452 |
14 | 661dca141d |
15 | 36d900d3ca |
hex | 1ef94651c3 |
133031154115 has 4 divisors (see below), whose sum is σ = 159637384944. Its totient is φ = 106424923288.
The previous prime is 133031154107. The next prime is 133031154127. The reversal of 133031154115 is 511451130331.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 511451130331 = 53 ⋅9650021327.
It is a cyclic number.
It is not a de Polignac number, because 133031154115 - 23 = 133031154107 is a prime.
It is a Duffinian number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13303115407 + ... + 13303115416.
It is an arithmetic number, because the mean of its divisors is an integer number (39909346236).
Almost surely, 2133031154115 is an apocalyptic number.
133031154115 is a deficient number, since it is larger than the sum of its proper divisors (26606230829).
133031154115 is an equidigital number, since it uses as much as digits as its factorization.
133031154115 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 26606230828.
The product of its (nonzero) digits is 2700, while the sum is 28.
Adding to 133031154115 its reverse (511451130331), we get a palindrome (644482284446).
The spelling of 133031154115 in words is "one hundred thirty-three billion, thirty-one million, one hundred fifty-four thousand, one hundred fifteen".
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