Base | Representation |
---|---|
bin | 1100000110010110010010… |
… | …1000011111111111101001 |
3 | 1202002202220000122202111200 |
4 | 3001211210220133333221 |
5 | 3220424424211212441 |
6 | 44143223500514413 |
7 | 2542060514500560 |
oct | 301454450377751 |
9 | 52082800582450 |
10 | 13303202054121 |
11 | 4269946822711 |
12 | 15aa2bb54ba09 |
13 | 756642cc47b5 |
14 | 33dc42528bd7 |
15 | 1810a7eec7b6 |
hex | c1964a1ffe9 |
13303202054121 has 24 divisors (see below), whose sum is σ = 22261674938880. Its totient is φ = 7497695088576.
The previous prime is 13303202054119. The next prime is 13303202054137. The reversal of 13303202054121 is 12145020230331.
13303202054121 is a `hidden beast` number, since 1 + 330 + 3 + 2 + 0 + 205 + 4 + 121 = 666.
It is not a de Polignac number, because 13303202054121 - 21 = 13303202054119 is a prime.
It is not an unprimeable number, because it can be changed into a prime (13303202054141) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 1446310041 + ... + 1446319238.
It is an arithmetic number, because the mean of its divisors is an integer number (927569789120).
Almost surely, 213303202054121 is an apocalyptic number.
It is an amenable number.
13303202054121 is a deficient number, since it is larger than the sum of its proper divisors (8958472884759).
13303202054121 is a wasteful number, since it uses less digits than its factorization.
13303202054121 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2892629365 (or 2892629362 counting only the distinct ones).
The product of its (nonzero) digits is 4320, while the sum is 27.
Adding to 13303202054121 its reverse (12145020230331), we get a palindrome (25448222284452).
The spelling of 13303202054121 in words is "thirteen trillion, three hundred three billion, two hundred two million, fifty-four thousand, one hundred twenty-one".
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