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1330328649659 = 9713714728347
BaseRepresentation
bin10011010110111101110…
…001000011111110111011
311201011210220001111011212
4103112331301003332323
5133244003113242114
62455051115513335
7165053532642452
oct23267561037673
94634726044155
101330328649659
11473209928609
121959b045884b
13985ac5ab799
1448561503b99
152491181bb3e
hex135bdc43fbb

1330328649659 has 4 divisors (see below), whose sum is σ = 1344043378104. Its totient is φ = 1316613921216.

The previous prime is 1330328649649. The next prime is 1330328649721. The reversal of 1330328649659 is 9569468230331.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1330328649659 - 212 = 1330328645563 is a prime.

It is a super-2 number, since 2×13303286496592 (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1330328649598 and 1330328649607.

It is not an unprimeable number, because it can be changed into a prime (1330328649649) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6857364077 + ... + 6857364270.

It is an arithmetic number, because the mean of its divisors is an integer number (336010844526).

Almost surely, 21330328649659 is an apocalyptic number.

1330328649659 is a deficient number, since it is larger than the sum of its proper divisors (13714728445).

1330328649659 is an equidigital number, since it uses as much as digits as its factorization.

1330328649659 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 13714728444.

The product of its (nonzero) digits is 25194240, while the sum is 59.

The spelling of 1330328649659 in words is "one trillion, three hundred thirty billion, three hundred twenty-eight million, six hundred forty-nine thousand, six hundred fifty-nine".

Divisors: 1 97 13714728347 1330328649659