13303402103041 has 4 divisors (see below), whose sum is σ = 13303409623812. Its totient is φ = 13303394582272.

The previous prime is 13303402103023. The next prime is 13303402103059. The reversal of 13303402103041 is 14030120430331.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It is an interprime number because it is at equal distance from previous prime (13303402103023) and next prime (13303402103059).

It can be written as a sum of positive squares in 2 ways, for example, as 6035546860225 + 7267855242816 = 2456735^2 + 2695896^2 .

It is a cyclic number.

It is not a de Polignac number, because 13303402103041 - 2¹³ = 13303402094849 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13303402102997 and 13303402103015.

It is not an unprimeable number, because it can be changed into a prime (13303402103081) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 507801 + ... + 5183113.

It is an arithmetic number, because the mean of its divisors is an integer number (3325852405953).

Almost surely, 2^{13303402103041} is an apocalyptic number.

It is an amenable number.

13303402103041 is a deficient number, since it is larger than the sum of its proper divisors (7520771).

13303402103041 is an equidigital number, since it uses as much as digits as its factorization.

13303402103041 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 7520770.

The product of its (nonzero) digits is 2592, while the sum is 25.

Adding to 13303402103041 its reverse (14030120430331), we get a palindrome (27333522533372).

The spelling of 13303402103041 in words is "thirteen trillion, three hundred three billion, four hundred two million, one hundred three thousand, forty-one".