Base | Representation |
---|---|
bin | 10011010110111110011… |
… | …110000000111000001111 |
3 | 11201011211201020011110120 |
4 | 103112332132000320033 |
5 | 133244014122332143 |
6 | 2455052220240023 |
7 | 165054035051451 |
oct | 23267636007017 |
9 | 4634751204416 |
10 | 1330340433423 |
11 | 473215546961 |
12 | 1959b43a0013 |
13 | 985b1b76221 |
14 | 48562cd02d1 |
15 | 24912898383 |
hex | 135be780e0f |
1330340433423 has 4 divisors (see below), whose sum is σ = 1773787244568. Its totient is φ = 886893622280.
The previous prime is 1330340433377. The next prime is 1330340433437. The reversal of 1330340433423 is 3243340430331.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1330340433423 - 213 = 1330340425231 is a prime.
It is a super-3 number, since 3×13303404334233 (a number of 37 digits) contains 333 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1330340433823) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 221723405568 + ... + 221723405573.
It is an arithmetic number, because the mean of its divisors is an integer number (443446811142).
Almost surely, 21330340433423 is an apocalyptic number.
1330340433423 is a deficient number, since it is larger than the sum of its proper divisors (443446811145).
1330340433423 is an equidigital number, since it uses as much as digits as its factorization.
1330340433423 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 443446811144.
The product of its (nonzero) digits is 93312, while the sum is 33.
Adding to 1330340433423 its reverse (3243340430331), we get a palindrome (4573680863754).
The spelling of 1330340433423 in words is "one trillion, three hundred thirty billion, three hundred forty million, four hundred thirty-three thousand, four hundred twenty-three".
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