Base | Representation |
---|---|
bin | 11110001111111111001100… |
… | …100001011110011100100011 |
3 | 122110001111121100212001010110 |
4 | 132033333030201132130203 |
5 | 114414212002042233443 |
6 | 1150541430244502403 |
7 | 40010553203446161 |
oct | 3617771441363443 |
9 | 573044540761113 |
10 | 133040043321123 |
11 | 39432a69120824 |
12 | 12b080753aaa03 |
13 | 5930812124a33 |
14 | 24bd25b2dc231 |
15 | 105aa244d0233 |
hex | 78ffcc85e723 |
133040043321123 has 16 divisors (see below), whose sum is σ = 186725572012800. Its totient is φ = 84024073631520.
The previous prime is 133040043321121. The next prime is 133040043321197. The reversal of 133040043321123 is 321123340040331.
It is not a de Polignac number, because 133040043321123 - 21 = 133040043321121 is a prime.
It is a super-2 number, since 2×1330400433211232 (a number of 29 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (133040043321121) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 12922728 + ... + 20810501.
It is an arithmetic number, because the mean of its divisors is an integer number (11670348250800).
Almost surely, 2133040043321123 is an apocalyptic number.
133040043321123 is a deficient number, since it is larger than the sum of its proper divisors (53685528691677).
133040043321123 is a wasteful number, since it uses less digits than its factorization.
133040043321123 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 33802442.
The product of its (nonzero) digits is 15552, while the sum is 30.
Adding to 133040043321123 its reverse (321123340040331), we get a palindrome (454163383361454).
The spelling of 133040043321123 in words is "one hundred thirty-three trillion, forty billion, forty-three million, three hundred twenty-one thousand, one hundred twenty-three".
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