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1330401244251 = 3643689684419
BaseRepresentation
bin10011010111000010000…
…101111111010001011011
311201011222221122200020110
4103113002011333101123
5133244130204304001
62455102231455403
7165055403663502
oct23270205772133
94634887580213
101330401244251
11473246900a42
12195a10827563
13985c1648271
144856addd839
1524917dab3d6
hex135c217f45b

1330401244251 has 8 divisors (see below), whose sum is σ = 1776627065920. Its totient is φ = 885554792712.

The previous prime is 1330401244231. The next prime is 1330401244253. The reversal of 1330401244251 is 1524421040331.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 1330401244251 - 29 = 1330401243739 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1330401244253) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 344840281 + ... + 344844138.

It is an arithmetic number, because the mean of its divisors is an integer number (222078383240).

Almost surely, 21330401244251 is an apocalyptic number.

1330401244251 is a deficient number, since it is larger than the sum of its proper divisors (446225821669).

1330401244251 is an equidigital number, since it uses as much as digits as its factorization.

1330401244251 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 689685065.

The product of its (nonzero) digits is 11520, while the sum is 30.

Adding to 1330401244251 its reverse (1524421040331), we get a palindrome (2854822284582).

The spelling of 1330401244251 in words is "one trillion, three hundred thirty billion, four hundred one million, two hundred forty-four thousand, two hundred fifty-one".

Divisors: 1 3 643 1929 689684419 2069053257 443467081417 1330401244251