1330403315213 has 4 divisors (see below), whose sum is σ = 1520460931680. Its totient is φ = 1140345698748.

The previous prime is 1330403315173. The next prime is 1330403315239. The reversal of 1330403315213 is 3125133040331.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1330403315213 - 2⁶ = 1330403315149 is a prime.

It is a super-3 number, since 3×1330403315213³ (a number of 37 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1330403315113) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 95028808223 + ... + 95028808236.

It is an arithmetic number, because the mean of its divisors is an integer number (380115232920).

Almost surely, 2^{1330403315213} is an apocalyptic number.

It is an amenable number.

1330403315213 is a deficient number, since it is larger than the sum of its proper divisors (190057616467).

1330403315213 is an equidigital number, since it uses as much as digits as its factorization.

1330403315213 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 190057616466.

The product of its (nonzero) digits is 9720, while the sum is 29.

Adding to 1330403315213 its reverse (3125133040331), we get a palindrome (4455536355544).

The spelling of 1330403315213 in words is "one trillion, three hundred thirty billion, four hundred three million, three hundred fifteen thousand, two hundred thirteen".