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133043455045 = 568993856891
BaseRepresentation
bin111101111101000000…
…0100000010001000101
3110201102000201210002001
41323322000200101011
54134433111030140
6141041434545301
712416640465064
oct1737200402105
9421360653061
10133043455045
115147261aa36
122194bb98231
13c7135923c7
1466217841db
1536da13ce9a
hex1efa020445

133043455045 has 8 divisors (see below), whose sum is σ = 159675328800. Its totient is φ = 106419308880.

The previous prime is 133043455043. The next prime is 133043455099. The reversal of 133043455045 is 540554340331.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 133043455045 - 21 = 133043455043 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 133043454995 and 133043455013.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (133043455043) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1893951 + ... + 1962940.

It is an arithmetic number, because the mean of its divisors is an integer number (19959416100).

Almost surely, 2133043455045 is an apocalyptic number.

It is an amenable number.

133043455045 is a deficient number, since it is larger than the sum of its proper divisors (26631873755).

133043455045 is an equidigital number, since it uses as much as digits as its factorization.

133043455045 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3863795.

The product of its (nonzero) digits is 216000, while the sum is 37.

Adding to 133043455045 its reverse (540554340331), we get a palindrome (673597795376).

The spelling of 133043455045 in words is "one hundred thirty-three billion, forty-three million, four hundred fifty-five thousand, forty-five".

Divisors: 1 5 6899 34495 3856891 19284455 26608691009 133043455045