13304354453 has 4 divisors (see below), whose sum is σ = 14327766348. Its totient is φ = 12280942560.

The previous prime is 13304354443. The next prime is 13304354507. The reversal of 13304354453 is 35445340331.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 35445340331 = 59621 ⋅594511.

It can be written as a sum of positive squares in 2 ways, for example, as 7405807249 + 5898547204 = 86057^2 + 76802^2 .

It is a cyclic number.

It is not a de Polignac number, because 13304354453 - 2¹² = 13304350357 is a prime.

It is a super-2 number, since 2×13304354453² (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13304354443) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 511705928 + ... + 511705953.

It is an arithmetic number, because the mean of its divisors is an integer number (3581941587).

Almost surely, 2^13304354453 is an apocalyptic number.

13304354453 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

It is an amenable number.

13304354453 is a deficient number, since it is larger than the sum of its proper divisors (1023411895).

13304354453 is a wasteful number, since it uses less digits than its factorization.

13304354453 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1023411894.

The product of its (nonzero) digits is 129600, while the sum is 35.

Adding to 13304354453 its reverse (35445340331), we get a palindrome (48749694784).

The spelling of 13304354453 in words is "thirteen billion, three hundred four million, three hundred fifty-four thousand, four hundred fifty-three".