1330444040113 has 4 divisors (see below), whose sum is σ = 1330915998960. Its totient is φ = 1329972081268.

The previous prime is 1330444040099. The next prime is 1330444040129. The reversal of 1330444040113 is 3110404440331.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1330444040113 - 2²⁵ = 1330410485681 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1330444047113) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 235975195 + ... + 235980832.

It is an arithmetic number, because the mean of its divisors is an integer number (332728999740).

Almost surely, 2^{1330444040113} is an apocalyptic number.

It is an amenable number.

1330444040113 is a deficient number, since it is larger than the sum of its proper divisors (471958847).

1330444040113 is an equidigital number, since it uses as much as digits as its factorization.

1330444040113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 471958846.

The product of its (nonzero) digits is 6912, while the sum is 28.

Adding to 1330444040113 its reverse (3110404440331), we get a palindrome (4440848480444).

The spelling of 1330444040113 in words is "one trillion, three hundred thirty billion, four hundred forty-four million, forty thousand, one hundred thirteen".