13305041433 has 12 divisors (see below), whose sum is σ = 19230358420. Its totient is φ = 8864505216.

The previous prime is 13305041417. The next prime is 13305041447. The reversal of 13305041433 is 33414050331.

13305041433 is a `hidden beast` number, since 13 + 3 + 0 + 504 + 143 + 3 = 666.

It can be written as a sum of positive squares in 2 ways, for example, as 7318460304 + 5986581129 = 85548^2 + 77373^2 .

It is not a de Polignac number, because 13305041433 - 2⁴ = 13305041417 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13305041397 and 13305041406.

It is not an unprimeable number, because it can be changed into a prime (13305042433) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 444916 + ... + 473877.

Almost surely, 2^13305041433 is an apocalyptic number.

It is an amenable number.

13305041433 is a deficient number, since it is larger than the sum of its proper divisors (5925316987).

13305041433 is a wasteful number, since it uses less digits than its factorization.

13305041433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 920408 (or 920405 counting only the distinct ones).

The product of its (nonzero) digits is 6480, while the sum is 27.

Adding to 13305041433 its reverse (33414050331), we get a palindrome (46719091764).

The spelling of 13305041433 in words is "thirteen billion, three hundred five million, forty-one thousand, four hundred thirty-three".