1330514050003 has 4 divisors (see below), whose sum is σ = 1330516805400. Its totient is φ = 1330511294608.

The previous prime is 1330514049989. The next prime is 1330514050049. The reversal of 1330514050003 is 3000504150331.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1330514050003 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 1330514050003.

It is not an unprimeable number, because it can be changed into a prime (1330514050303) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 441178 + ... + 1689871.

It is an arithmetic number, because the mean of its divisors is an integer number (332629201350).

Almost surely, 2^{1330514050003} is an apocalyptic number.

1330514050003 is a deficient number, since it is larger than the sum of its proper divisors (2755397).

1330514050003 is an equidigital number, since it uses as much as digits as its factorization.

1330514050003 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2755396.

The product of its (nonzero) digits is 2700, while the sum is 25.

The spelling of 1330514050003 in words is "one trillion, three hundred thirty billion, five hundred fourteen million, fifty thousand, three".