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1330515454045 = 5266103090809
BaseRepresentation
bin10011010111001000111…
…001101010100001011101
311201012021220120010121211
4103113020321222201131
5133244343424012140
62455121431424421
7165061261520611
oct23271071524135
94635256503554
101330515454045
114732a53184a8
12195a42b25111
139860c1c581b
144857c24d341
1524922e1b2ea
hex135c8e6a85d

1330515454045 has 4 divisors (see below), whose sum is σ = 1596618544860. Its totient is φ = 1064412363232.

The previous prime is 1330515454019. The next prime is 1330515454111. The reversal of 1330515454045 is 5404545150331.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 775009079716 + 555506374329 = 880346^2 + 745323^2 .

It is a cyclic number.

It is not a de Polignac number, because 1330515454045 - 25 = 1330515454013 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1330515453989 and 1330515454007.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 133051545400 + ... + 133051545409.

It is an arithmetic number, because the mean of its divisors is an integer number (399154636215).

Almost surely, 21330515454045 is an apocalyptic number.

It is an amenable number.

1330515454045 is a deficient number, since it is larger than the sum of its proper divisors (266103090815).

1330515454045 is an equidigital number, since it uses as much as digits as its factorization.

1330515454045 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 266103090814.

The product of its (nonzero) digits is 360000, while the sum is 40.

The spelling of 1330515454045 in words is "one trillion, three hundred thirty billion, five hundred fifteen million, four hundred fifty-four thousand, forty-five".

Divisors: 1 5 266103090809 1330515454045