Base | Representation |
---|---|
bin | 11110010000001011010010… |
… | …000000000101111011101111 |
3 | 122110002202002202000111102020 |
4 | 132100023102000011323233 |
5 | 114414420041123311101 |
6 | 1150551414051001223 |
7 | 40011522605525214 |
oct | 3620132200057357 |
9 | 573082082014366 |
10 | 133053020135151 |
11 | 394385181aa216 |
12 | 12b0a697299213 |
13 | 5931acc76910c |
14 | 24bdb2c94db0b |
15 | 105b0338a2136 |
hex | 7902d2005eef |
133053020135151 has 16 divisors (see below), whose sum is σ = 186771739904640. Its totient is φ = 84019689845280.
The previous prime is 133053020135149. The next prime is 133053020135201. The reversal of 133053020135151 is 151531020350331.
It is not a de Polignac number, because 133053020135151 - 21 = 133053020135149 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (133053020135851) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 191268600 + ... + 191962973.
It is an arithmetic number, because the mean of its divisors is an integer number (11673233744040).
Almost surely, 2133053020135151 is an apocalyptic number.
133053020135151 is a deficient number, since it is larger than the sum of its proper divisors (53718719769489).
133053020135151 is a wasteful number, since it uses less digits than its factorization.
133053020135151 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 383237686.
The product of its (nonzero) digits is 20250, while the sum is 33.
Adding to 133053020135151 its reverse (151531020350331), we get a palindrome (284584040485482).
The spelling of 133053020135151 in words is "one hundred thirty-three trillion, fifty-three billion, twenty million, one hundred thirty-five thousand, one hundred fifty-one".
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