133053341504351 has 4 divisors (see below), whose sum is σ = 133400739263232. Its totient is φ = 132705943745472.

The previous prime is 133053341504341. The next prime is 133053341504353. The reversal of 133053341504351 is 153405143350331.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-133053341504351 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 133053341504299 and 133053341504308.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (133053341504353) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 173698878866 + ... + 173698879631.

It is an arithmetic number, because the mean of its divisors is an integer number (33350184815808).

Almost surely, 2^{133053341504351} is an apocalyptic number.

133053341504351 is a deficient number, since it is larger than the sum of its proper divisors (347397758881).

133053341504351 is an equidigital number, since it uses as much as digits as its factorization.

133053341504351 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 347397758880.

The product of its (nonzero) digits is 486000, while the sum is 41.

Adding to 133053341504351 its reverse (153405143350331), we get a palindrome (286458484854682).

The spelling of 133053341504351 in words is "one hundred thirty-three trillion, fifty-three billion, three hundred forty-one million, five hundred four thousand, three hundred fifty-one".