13305340453 has 4 divisors (see below), whose sum is σ = 13310010208. Its totient is φ = 13300670700.

The previous prime is 13305340441. The next prime is 13305340471. The reversal of 13305340453 is 35404350331.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13305340453 - 2⁵ = 13305340421 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13305340493) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2330601 + ... + 2336302.

It is an arithmetic number, because the mean of its divisors is an integer number (3327502552).

Almost surely, 2^13305340453 is an apocalyptic number.

It is an amenable number.

13305340453 is a deficient number, since it is larger than the sum of its proper divisors (4669755).

13305340453 is an equidigital number, since it uses as much as digits as its factorization.

13305340453 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4669754.

The product of its (nonzero) digits is 32400, while the sum is 31.

Adding to 13305340453 its reverse (35404350331), we get a palindrome (48709690784).

The spelling of 13305340453 in words is "thirteen billion, three hundred five million, three hundred forty thousand, four hundred fifty-three".