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133054515053 = 139957226727
BaseRepresentation
bin111101111101010101…
…0101100011101101101
3110201102210112200112222
41323322222230131231
54134443423440203
6141042512005125
712420133501025
oct1737252543555
9421383480488
10133054515053
1151478894539
12219538307a5
13c7159655a5
146623022a85
1536db0c5038
hex1efaaac76d

133054515053 has 4 divisors (see below), whose sum is σ = 134011741920. Its totient is φ = 132097288188.

The previous prime is 133054515037. The next prime is 133054515059. The reversal of 133054515053 is 350515450331.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 133054515053 - 24 = 133054515037 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (133054515059) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 478613225 + ... + 478613502.

It is an arithmetic number, because the mean of its divisors is an integer number (33502935480).

Almost surely, 2133054515053 is an apocalyptic number.

It is an amenable number.

133054515053 is a deficient number, since it is larger than the sum of its proper divisors (957226867).

133054515053 is an equidigital number, since it uses as much as digits as its factorization.

133054515053 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 957226866.

The product of its (nonzero) digits is 67500, while the sum is 35.

Adding to 133054515053 its reverse (350515450331), we get a palindrome (483569965384).

The spelling of 133054515053 in words is "one hundred thirty-three billion, fifty-four million, five hundred fifteen thousand, fifty-three".

Divisors: 1 139 957226727 133054515053