1331000120213 has 4 divisors (see below), whose sum is σ = 1331594584320. Its totient is φ = 1330405656108.

The previous prime is 1331000120209. The next prime is 1331000120227. The reversal of 1331000120213 is 3120210001331.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1331000120213 - 2² = 1331000120209 is a prime.

It is a super-2 number, since 2×1331000120213² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1331000120191 and 1331000120200.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1331000120243) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 297228695 + ... + 297233172.

It is an arithmetic number, because the mean of its divisors is an integer number (332898646080).

Almost surely, 2^{1331000120213} is an apocalyptic number.

It is an amenable number.

1331000120213 is a deficient number, since it is larger than the sum of its proper divisors (594464107).

1331000120213 is an equidigital number, since it uses as much as digits as its factorization.

1331000120213 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 594464106.

The product of its (nonzero) digits is 108, while the sum is 17.

Adding to 1331000120213 its reverse (3120210001331), we get a palindrome (4451210121544).

The spelling of 1331000120213 in words is "one trillion, three hundred thirty-one billion, one hundred twenty thousand, two hundred thirteen".