133100100020011 has 4 divisors (see below), whose sum is σ = 135611422661952. Its totient is φ = 130588777378072.

The previous prime is 133100100019987. The next prime is 133100100020021. The reversal of 133100100020011 is 110020001001331.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 133100100020011 - 2⁵ = 133100100019979 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 133100100019973 and 133100100020000.

It is not an unprimeable number, because it can be changed into a prime (133100100020021) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1255661320891 + ... + 1255661320996.

It is an arithmetic number, because the mean of its divisors is an integer number (33902855665488).

Almost surely, 2^{133100100020011} is an apocalyptic number.

133100100020011 is a deficient number, since it is larger than the sum of its proper divisors (2511322641941).

133100100020011 is an equidigital number, since it uses as much as digits as its factorization.

133100100020011 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2511322641940.

The product of its (nonzero) digits is 18, while the sum is 13.

Adding to 133100100020011 its reverse (110020001001331), we get a palindrome (243120101021342).

The spelling of 133100100020011 in words is "one hundred thirty-three trillion, one hundred billion, one hundred million, twenty thousand, eleven".