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133100200004 = 2233275050001
BaseRepresentation
bin111101111110101100…
…0111110000001000100
3110201112222111201112012
41323331120332001010
54140042122400004
6141051223113352
712421230014222
oct1737530760104
9421488451465
10133100200004
11514a16582a2
1221966ba2858
13c72226c8c5
146629115b12
1536e00eb46e
hex1efd63e044

133100200004 has 6 divisors (see below), whose sum is σ = 232925350014. Its totient is φ = 66550100000.

The previous prime is 133100199997. The next prime is 133100200007. The reversal of 133100200004 is 400002001331.

It can be written as a sum of positive squares in only one way, i.e., 75092440900 + 58007759104 = 274030^2 + 240848^2 .

It is a super-2 number, since 2×1331002000042 (a number of 23 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (133100200007) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 16637524997 + ... + 16637525004.

It is an arithmetic number, because the mean of its divisors is an integer number (38820891669).

Almost surely, 2133100200004 is an apocalyptic number.

It is an amenable number.

133100200004 is a deficient number, since it is larger than the sum of its proper divisors (99825150010).

133100200004 is a wasteful number, since it uses less digits than its factorization.

133100200004 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 33275050005 (or 33275050003 counting only the distinct ones).

The product of its (nonzero) digits is 72, while the sum is 14.

Adding to 133100200004 its reverse (400002001331), we get a palindrome (533102201335).

The spelling of 133100200004 in words is "one hundred thirty-three billion, one hundred million, two hundred thousand, four".

Divisors: 1 2 4 33275050001 66550100002 133100200004