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1331002135 = 5266200427
BaseRepresentation
bin100111101010101…
…0111101100010111
310102202111220200101
41033111113230113
510211214032020
6340023554531
744661221461
oct11725275427
93382456611
101331002135
11623352671
123118bba47
131829a1138
14c8ab1131
157bcb600a
hex4f557b17

1331002135 has 4 divisors (see below), whose sum is σ = 1597202568. Its totient is φ = 1064801704.

The previous prime is 1331002129. The next prime is 1331002201. The reversal of 1331002135 is 5312001331.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1331002135 is a prime.

It is a Duffinian number.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 133100209 + ... + 133100218.

It is an arithmetic number, because the mean of its divisors is an integer number (399300642).

Almost surely, 21331002135 is an apocalyptic number.

1331002135 is a deficient number, since it is larger than the sum of its proper divisors (266200433).

1331002135 is an equidigital number, since it uses as much as digits as its factorization.

1331002135 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 266200432.

The product of its (nonzero) digits is 270, while the sum is 19.

The square root of 1331002135 is about 36482.9019542031. The cubic root of 1331002135 is about 1100.0005881540. Note that the first 3 decimals are identical.

Adding to 1331002135 its reverse (5312001331), we get a palindrome (6643003466).

The spelling of 1331002135 in words is "one billion, three hundred thirty-one million, two thousand, one hundred thirty-five".

Divisors: 1 5 266200427 1331002135