13310111420303 has 4 divisors (see below), whose sum is σ = 13739469853248. Its totient is φ = 12880752987360.

The previous prime is 13310111420299. The next prime is 13310111420311. The reversal of 13310111420303 is 30302411101331.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13310111420303 - 2² = 13310111420299 is a prime.

It is a super-2 number, since 2×13310111420303² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13310111420393) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 214679216426 + ... + 214679216487.

It is an arithmetic number, because the mean of its divisors is an integer number (3434867463312).

Almost surely, 2^{13310111420303} is an apocalyptic number.

13310111420303 is a deficient number, since it is larger than the sum of its proper divisors (429358432945).

13310111420303 is an equidigital number, since it uses as much as digits as its factorization.

13310111420303 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 429358432944.

The product of its (nonzero) digits is 648, while the sum is 23.

Adding to 13310111420303 its reverse (30302411101331), we get a palindrome (43612522521634).

The spelling of 13310111420303 in words is "thirteen trillion, three hundred ten billion, one hundred eleven million, four hundred twenty thousand, three hundred three".