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1331012088143 = 1970053267797
BaseRepresentation
bin10011010111100110100…
…000001011000101001111
311201020120112001202112022
4103113212200023011033
5133301403043310033
62455243012200355
7165106502035463
oct23274640130517
94636515052468
101331012088143
1147352a696001
12195b613090bb
139868b06c85a
14485c81aa4a3
152495181c098
hex135e680b14f

1331012088143 has 4 divisors (see below), whose sum is σ = 1401065355960. Its totient is φ = 1260958820328.

The previous prime is 1331012088139. The next prime is 1331012088173. The reversal of 1331012088143 is 3418802101331.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1331012088143 - 22 = 1331012088139 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1331012088173) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 35026633880 + ... + 35026633917.

It is an arithmetic number, because the mean of its divisors is an integer number (350266338990).

Almost surely, 21331012088143 is an apocalyptic number.

1331012088143 is a deficient number, since it is larger than the sum of its proper divisors (70053267817).

1331012088143 is an equidigital number, since it uses as much as digits as its factorization.

1331012088143 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 70053267816.

The product of its (nonzero) digits is 13824, while the sum is 35.

Adding to 1331012088143 its reverse (3418802101331), we get a palindrome (4749814189474).

The spelling of 1331012088143 in words is "one trillion, three hundred thirty-one billion, twelve million, eighty-eight thousand, one hundred forty-three".

Divisors: 1 19 70053267797 1331012088143