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1331013120143 = 7487390440927
BaseRepresentation
bin10011010111100110100…
…100000111000010001111
311201020120121000012011112
4103113212210013002033
5133301403324321033
62455243050242235
7165106513564310
oct23274644070217
94636517005145
101331013120143
114735302303a3
12195b6172637b
139868b3414c5
14485c8398607
1524951972c48
hex135e690708f

1331013120143 has 8 divisors (see below), whose sum is σ = 1524281382912. Its totient is φ = 1138525740216.

The previous prime is 1331013120139. The next prime is 1331013120161. The reversal of 1331013120143 is 3410213101331.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 1331013120143 - 22 = 1331013120139 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1331013120643) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 195217055 + ... + 195223872.

It is an arithmetic number, because the mean of its divisors is an integer number (190535172864).

Almost surely, 21331013120143 is an apocalyptic number.

1331013120143 is a deficient number, since it is larger than the sum of its proper divisors (193268262769).

1331013120143 is an equidigital number, since it uses as much as digits as its factorization.

1331013120143 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 390441421.

The product of its (nonzero) digits is 648, while the sum is 23.

Adding to 1331013120143 its reverse (3410213101331), we get a palindrome (4741226221474).

The spelling of 1331013120143 in words is "one trillion, three hundred thirty-one billion, thirteen million, one hundred twenty thousand, one hundred forty-three".

Divisors: 1 7 487 3409 390440927 2733086489 190144731449 1331013120143