133101443113 has 4 divisors (see below), whose sum is σ = 134322557380. Its totient is φ = 131880328848.

The previous prime is 133101443087. The next prime is 133101443129. The reversal of 133101443113 is 311344101331.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 311344101331 = 19 ⋅16386531649.

It can be written as a sum of positive squares in 2 ways, for example, as 61012952064 + 72088491049 = 247008^2 + 268493^2 .

It is a cyclic number.

It is not a de Polignac number, because 133101443113 - 2⁵ = 133101443081 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (133101423113) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 610556970 + ... + 610557187.

It is an arithmetic number, because the mean of its divisors is an integer number (33580639345).

Almost surely, 2^133101443113 is an apocalyptic number.

It is an amenable number.

133101443113 is a deficient number, since it is larger than the sum of its proper divisors (1221114267).

133101443113 is a wasteful number, since it uses less digits than its factorization.

133101443113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1221114266.

The product of its (nonzero) digits is 1296, while the sum is 25.

Adding to 133101443113 its reverse (311344101331), we get a palindrome (444445544444).

The spelling of 133101443113 in words is "one hundred thirty-three billion, one hundred one million, four hundred forty-three thousand, one hundred thirteen".