Base | Representation |
---|---|
bin | 1100000110110000011001… |
… | …0110110111111111111111 |
3 | 1202010102222102221001102112 |
4 | 3001230012112313333333 |
5 | 3221033302314411033 |
6 | 44150343132044235 |
7 | 2542426263624065 |
oct | 301540626677777 |
9 | 52112872831375 |
10 | 13310210310143 |
11 | 42719127a613a |
12 | 15ab73660367b |
13 | 7571bbc2b556 |
14 | 3403091d4035 |
15 | 1813683e7c48 |
hex | c1b065b7fff |
13310210310143 has 4 divisors (see below), whose sum is σ = 13310218031040. Its totient is φ = 13310202589248.
The previous prime is 13310210310049. The next prime is 13310210310181. The reversal of 13310210310143 is 34101301201331.
It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.
It is a cyclic number.
It is not a de Polignac number, because 13310210310143 - 212 = 13310210306047 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13310210310443) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 37103 + ... + 5159631.
It is an arithmetic number, because the mean of its divisors is an integer number (3327554507760).
Almost surely, 213310210310143 is an apocalyptic number.
13310210310143 is a deficient number, since it is larger than the sum of its proper divisors (7720897).
13310210310143 is an equidigital number, since it uses as much as digits as its factorization.
13310210310143 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7720896.
The product of its (nonzero) digits is 648, while the sum is 23.
Adding to 13310210310143 its reverse (34101301201331), we get a palindrome (47411511511474).
The spelling of 13310210310143 in words is "thirteen trillion, three hundred ten billion, two hundred ten million, three hundred ten thousand, one hundred forty-three".
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