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13310233400431 = 111210021218221
BaseRepresentation
bin1100000110110000011110…
…1110111101010001101111
31202010110001001101011100101
43001230013232331101233
53221033324222303211
644150345315011531
72542426664113522
oct301540756752157
952113031334311
1013310233400431
114271924837220
1215ab742299ba7
137571c3954446
1434030c2c4bb9
1518136a4595c1
hexc1b07bbd46f

13310233400431 has 4 divisors (see below), whose sum is σ = 14520254618664. Its totient is φ = 12100212182200.

The previous prime is 13310233400411. The next prime is 13310233400491. The reversal of 13310233400431 is 13400433201331.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13310233400431 is a prime.

It is a super-2 number, since 2×133102334004312 (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 13310233400431.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13310233400411) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 605010609100 + ... + 605010609121.

It is an arithmetic number, because the mean of its divisors is an integer number (3630063654666).

Almost surely, 213310233400431 is an apocalyptic number.

13310233400431 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

13310233400431 is a deficient number, since it is larger than the sum of its proper divisors (1210021218233).

13310233400431 is a wasteful number, since it uses less digits than its factorization.

13310233400431 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1210021218232.

The product of its (nonzero) digits is 7776, while the sum is 28.

Adding to 13310233400431 its reverse (13400433201331), we get a palindrome (26710666601762).

It can be divided in two parts, 133102 and 33400431, that added together give a palindrome (33533533).

The spelling of 13310233400431 in words is "thirteen trillion, three hundred ten billion, two hundred thirty-three million, four hundred thousand, four hundred thirty-one".

Divisors: 1 11 1210021218221 13310233400431