1331024312041 has 4 divisors (see below), whose sum is σ = 1332472652800. Its totient is φ = 1329575971284.

The previous prime is 1331024311973. The next prime is 1331024312063. The reversal of 1331024312041 is 1402134201331.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1331024312041 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1331024311997 and 1331024312015.

It is not an unprimeable number, because it can be changed into a prime (1331024312071) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 724169001 + ... + 724170838.

It is an arithmetic number, because the mean of its divisors is an integer number (333118163200).

Almost surely, 2^{1331024312041} is an apocalyptic number.

It is an amenable number.

1331024312041 is a deficient number, since it is larger than the sum of its proper divisors (1448340759).

1331024312041 is an equidigital number, since it uses as much as digits as its factorization.

1331024312041 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1448340758.

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 1331024312041 its reverse (1402134201331), we get a palindrome (2733158513372).

The spelling of 1331024312041 in words is "one trillion, three hundred thirty-one billion, twenty-four million, three hundred twelve thousand, forty-one".