Base | Representation |
---|---|
bin | 10011010111100111100… |
… | …100111011010001000111 |
3 | 11201020121202222102122202 |
4 | 103113213210323101013 |
5 | 133301422202030203 |
6 | 2455244454345115 |
7 | 165110111162234 |
oct | 23274744732107 |
9 | 4636552872582 |
10 | 1331030111303 |
11 | 473539886082 |
12 | 195b6735b19b |
13 | 98691a10249 |
14 | 485ca73c78b |
15 | 249531cc388 |
hex | 135e793b447 |
1331030111303 has 4 divisors (see below), whose sum is σ = 1331259091848. Its totient is φ = 1330801130760.
The previous prime is 1331030111287. The next prime is 1331030111309. The reversal of 1331030111303 is 3031110301331.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1331030111303 - 24 = 1331030111287 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1331030111309) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 114481553 + ... + 114493178.
It is an arithmetic number, because the mean of its divisors is an integer number (332814772962).
Almost surely, 21331030111303 is an apocalyptic number.
1331030111303 is a deficient number, since it is larger than the sum of its proper divisors (228980545).
1331030111303 is an equidigital number, since it uses as much as digits as its factorization.
1331030111303 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 228980544.
The product of its (nonzero) digits is 243, while the sum is 20.
Adding to 1331030111303 its reverse (3031110301331), we get a palindrome (4362140412634).
The spelling of 1331030111303 in words is "one trillion, three hundred thirty-one billion, thirty million, one hundred eleven thousand, three hundred three".
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